SOLUTION: A rectangular piece of cardboard that is 15 inches by 18 inches is used to create a box. Squares with sides of length x are cut out of each of the corners. The flaps are then folde

Algebra ->  Equations -> SOLUTION: A rectangular piece of cardboard that is 15 inches by 18 inches is used to create a box. Squares with sides of length x are cut out of each of the corners. The flaps are then folde      Log On


   

Question 1200062: A rectangular piece of cardboard that is 15 inches by 18 inches is used to create a box. Squares with sides of length x are cut out of each of the corners. The flaps are then folded up to create the walls of the box and leave an internal base of 130 square inches.
a. Write an equation that models the information and can be solved for x
b. solve for x
c. Determine the volume of the box
Answer by josgarithmetic(39623) About Me  (Show Source):
You can put this solution on YOUR website!
"Internal base area"? Do we need to know the thickness of the carboard?

Just looking at base area, ignoring material thickness
%2815-2x%29%2818-2x%29=130
That's to start.
More than one way to go.

You might recognize the possibility to find two factors of 130 which differ by 3. They would be 10 and 13. Try using that.

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%2815-2x%29%2818-2x%29=10%2A13=130

system%2815-2x=10%2C18-2x=13%29
5=2x
x=2%261%2F2

VOLUME is %282.5%29%2810%29%2813%29=youcomputethis.