Question 1199999: I am thinking of a number, when divided by 9 the remainder is 4. When divided by 5 the remainder is 4 and when divided by 3 the remainder is 1. What number am I thinking of?
Found 2 solutions by MathLover1, greenestamps:
Answer by MathLover1(20849)   (Show Source):
You can put this solution on YOUR website! given:
a number,
when divided by  the remainder is 
when divided by  the remainder is
when divided by  the remainder is 
first find multiples
Series one: multiples of  plus  ->  ,  ,  ,  , , ,..........
Series two: multiple of  plus -> ,  ,  ,  ,  ,  , , ,,.................
Series three: multiple of  plus  ->,  ,  ,  ,  , , , , .,, ,, , ,,...
first common:
answer: the least number is
or, simply
so, use
The least number is
Answer by greenestamps(13200)  (Show Source):
You can put this solution on YOUR website!
The given information that the number divided by 3 leaves remainder 1 is superfluous, because 9 is a multiple of 3 and the remainder when divided by 9 is 4.
So the simplified problem is to find a number that leaves remainder 4 when divided by either 5 or 9. But if the remainder is 4 when divided by either 5 or 9, then the remainder is 4 when divided by 5*9=45.
So the given number could be any number that is 4 more than a multiple of 45.
One simple obvious such number is 4+45 = 49.
But other possibilities are 4+2(45) = 94, or 4+10(45) = 454, or even 4+(-3)(45) = -131.
ANSWER (the PROBABLE expected one): 49
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