SOLUTION: The length of a rectangle is 3 cm more than 5 times its width. If the area of the rectangle is 62 cm^2, find the dimensions of the rectangle to the nearest thousandth.

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Question 119998: The length of a rectangle is 3 cm more than 5 times its width. If the area of the rectangle is 62 cm^2, find the dimensions of the rectangle to the nearest thousandth.
Answer by checkley71(8403) About Me  (Show Source):
You can put this solution on YOUR website!
LENGTH=5W+3
WIDTH=W
62=W(5W+3)
62=5W^2+3W
5W^2+3W-62=0
USING THE QUADRATIC EQUATION x+=+%28-b+%2B-+sqrt%28+b%5E2-4%2Aa%2Ac+%29%29%2F%282%2Aa%29+ WE GET:
W=(-3+-SQRT[3^2-4*5*-62])/2*5
W=(-3+-SQRT[9+1240])/10
W=(-3+-SQRT1249)/10
W=(-3+-35.341)/10
W=(-3+35.341)/10
W=32.341/10
W=3.234 ANSWER FOR THE WIDTH.
L=5*3.234+3
L=16.17+3
L=19.17 ANSWER FOR THE LENGTH.
PROOF
3.234*19.17=62
62=62