SOLUTION: Find the product xy, where x and y are positive integers and {{{0=3x^4-x^3*y-9317}}}

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Question 1199929: Find the product xy, where x and y are positive integers and 0=3x%5E4-x%5E3%2Ay-9317
Found 2 solutions by Yoshi16, MathTherapy:
Answer by Yoshi16(1) About Me  (Show Source):
You can put this solution on YOUR website!
The above equation can be re written as
3x%5E4-x%5E3%2Ay+=+9317
then we can factor out an x%5E3 term
x%5E3%283x-y%29+=+9317
then we can prime factorize 9317, which gives us 7+%2A+11%5E3
which means that from our above factored equation, x can be either 1 or 11
if x = 1
3x+-+y+=+7
-y+=+4
y+=+-4
since we get a negative value of y, x can only be 11
+3%2811%29+-+y+=+7
-y+=+-26
y+=+26
therefore the product of x and y is 286
cheers

Answer by MathTherapy(10552) About Me  (Show Source):
You can put this solution on YOUR website!
Find the product xy, where x and y are positive integers and 0=3x%5E4-x%5E3%2Ay-9317
                 

                  ---- Prime factors of 9,317: 7(113), or (113)7

                  ------ Equating terms on left and right sides

                      matrix%281%2C3%2C+x%5E3+%3C%3E+7%2C+and%2C+3x+-+y+%3C%3E+11%5E3%29, since x and y will NOT be INTEGERS, and it's stated that x and y are POSITIVE INTEGERS.

           Therefore, matrix%281%2C3%2C+x%5E3%2C+%22=%22%2C+11%5E3%29 and so, x = 11 (EXPONENTS are equal and so are their BASES).
                           Also, 

                                  So, highlight_green%28matrix%281%2C5%2C+xy%2C+%22=%22%2C+11%2826%29%2C+%22=%22%2C+286%29%29