SOLUTION: Buduli covers a distance of 8km to his house in 1hour.He walks part of the distance at 6km/h and runs the rest at 10km/h. How many kilometers did he run.

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Question 1199900: Buduli covers a distance of 8km to his house in 1hour.He walks part of the distance at 6km/h
and runs the rest at 10km/h. How many kilometers did he run.
Found 2 solutions by ikleyn, MathTherapy:
Answer by ikleyn(52794) About Me  (Show Source):
You can put this solution on YOUR website!
.
Buduli covers a distance of 8 km to his house in 1 hour.He walks part of
the distance at 6 km/h and runs the rest at 10 km/h. How many kilometers did he run.
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Let d be the distance he ran, in kilometers.

Then the distance he walked was (8-d) kilometers.


Write the time equation

    d%2F10 + %288-d%29%2F6 = 1  hour.


To solve it, multiply both sides of equation by 30.  You will get

    3d + 5*(8-d) = 30.


Simplify and find d

    3d + 40 - 5d = 30

    40 - 30 = 5d - 3d

      10    =   2d

       d    =    10/2 = 5.


ANSWER.  Buduli ran 5 kilometers.


CHECK.   5%2F10 + %288-5%29%2F6 = 5%2F10 + 3%2F6 = 1%2F2 + 1%2F2 = 1 hour, the total time.   ! correct !

Solved.



Answer by MathTherapy(10552) About Me  (Show Source):
You can put this solution on YOUR website!
Buduli covers a distance of 8km to his house in 1hour.He walks part of the distance at 6km/h and runs the rest at 10km/h. How many kilometers did he run.

Let distance he ran be D
Then distance walked = 8 - D
Time taken to run and walk the 2 distances: matrix%281%2C4%2C+D%2F10%2C+and%2C+%288+-+D%29%2F6%2C+respectively%29

We then get the following TIME equation: matrix%281%2C3%2C+D%2F10+%2B+%288+-+D%29%2F6%2C+%22=%22%2C+1%29
                                      3D + 5(8 - D) = 30 ---- Multiplying by LCD, 30
                                       3D + 40 - 5D = 30
                                            3D - 5D = 30 - 40
                                               - 2D = - 10
                             Distance he ran, or