SOLUTION: I need help solving a problem that says, write an equation of the line that is perpendicular to the line 5y + 2x = 13 and passes through the (6, 2). Write the answer in s

Algebra ->  Linear-equations -> SOLUTION: I need help solving a problem that says, write an equation of the line that is perpendicular to the line 5y + 2x = 13 and passes through the (6, 2). Write the answer in s      Log On


   

Question 119985: I need help solving a problem that says, write an equation of the line that is

perpendicular to the line 5y + 2x = 13 and
passes through the (6, 2). Write the answer in slope-intercept form or standard form.

Answer by checkley71(8403) About Me  (Show Source):
You can put this solution on YOUR website!
5Y+2X=13
5Y=-2X+13
Y=-2X/5+13/5 THUS THIS LINE HAS A SLOPE OF -2/5. (RED LINE)
FOR THE PERPENDICULAR LINE THE SLOPE IS THE NEGATIVE RECIPRICAL OF THIS SLOPE OR 5/2.
USING THE POINT(6,2 & THE SLOPE OF 5/2 WE SOLVE THE LINE EQUATION FOR THE Y INTERCEPT(b)
2=5/2*6+b
2=30/2+b
b=2-15
b=-13 FOR THIS Y INTERCEPT.
y=5x/2-13 (GREEN LINE)
+graph%28+400%2C+400%2C+-6%2C+15%2C+-15%2C+15%2C+y+=+-2x%2F5+%2B13%2C+y+=+5x%2F2+-13%29+ (graph 400x400 pixels, x from -6 to 15, y from -15 to 15, of TWO functions y = -2x/5 +13 and y = 5x/2 -13).