|
Question 1199828: 7.
Let q represent the number of widgets sold each week by a store, p represent the price in dollars of a widget, and D represent the demand.
Suppose that the demand function is q=D(p)= 120/square root of p
.
What is the decrease in the demand when p is changed from $9 to $25?
Second question - Let f(x,y)=5y+10x what would be the value of f(6,2)
Answer by math_tutor2020(3817)   (Show Source):
You can put this solution on YOUR website!
Problem 1
Plug in p = 9 to find q = D(p)
Repeat for p = 25
The demand goes from 40 to 24, which is a decrease of 16 (since 40-24 = 16).
==============================================
Problem 2
The given function is
f(x,y) = 5y+10x
We want to find f(6,2)
Wherever you see 'x', replace it with 6.
Wherever you see 'y', replace it with 2.
Then simplify.
f(x,y) = 5y+10x
f(6,y) = 5y+10*6 ...... replace x with 6
f(6,2) = 5*2+10*6 ...... replace y with 2
f(6,2) = 10+60
f(6,2) = 70
|
|
|
| |
