SOLUTION: I have to do elimination with this but I don't know what to multiply it by. I am getting weird fractions but I know it is incorrect. 8x-7y=-6 7x-8y=-9

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Question 1199812: I have to do elimination with this but I don't know what to multiply it by. I am getting weird fractions but I know it is incorrect.
8x-7y=-6
7x-8y=-9

Found 3 solutions by josgarithmetic, math_tutor2020, ikleyn:
Answer by josgarithmetic(39617) About Me  (Show Source):
You can put this solution on YOUR website!
8x-7y=-6
7x-8y=-9

system%288x-7y=-6+%2C7x-8y=-9%29
8*E1 and -7*E2:

------------------
8(8x-7y)=8(-6)
7(7x-8y)=7(-9)
------------------

---------------
64x-56y=-48
49x-56y=-63
---------------

-------------
64x-56y=-48
-49x+56y=63
-------------

ADD

15x=15
x=1


Return to original and do 7*E1 and 8*E2;

------------
56x-49y=-42
56x-64y=-72
------------

(-1)E2

----------------
56x-49y=-42
-56x+64y=72
----------------

ADD
15y=30
y=2


Intersection point, (1,2).

Answer by math_tutor2020(3817) About Me  (Show Source):
You can put this solution on YOUR website!

Let's say we wanted to eliminate the variable y.

The y terms from the 1st and 2nd equations are -7y and -8y respectively.

The coefficients -7 and -8 do not add to zero. To fix this, we can multiply both sides of the first equation by 8 and the second equation by -7

8x-7y = -6 becomes 64x-56y = -48
7x-8y = -9 becomes -49x+56y = 63

At this point the y terms are -56y and 56y. They add to 0y or simply 0. The y variables are eliminated.

Add the x terms: 64x+(-49x) = 15x
Add the right hand side constants: -48+63 = 15

We arrive at 15x = 15 which solves to x = 1.

Once we determine x, use it to find the value of y.
8x-7y = -6
8*1-7y = -6
8-7y = -6
-7y = -6-8
-7y = -14
y = -14/(-7)
y = 2

The solution is (x,y) = (1,2)

--------------------------------------
Check:

Plug x = 1 and y = 2 into the first original equation
8x-7y = -6
8*1-7*2 = -6
8-14 = -6
-6 = -6
That equation is confirmed.

Repeat for the other original equation
7x-8y = -9
7*1-8*2 = -9
7-16 = -9
-9 = -9
Both equations are confirmed.

Another way to check the answer is to use a graphing tool like Desmos or GeoGebra to plot each of the original lines separately
The two lines 8x-7y = -6 and 7x-8y = -9 intersect at (1,2)

8x-7y = -6 in green
7x-8y = -9 in blue

Here is the link to the interactive Desmos graph
https://www.desmos.com/calculator/uwnrw4zpj9

Answer by ikleyn(52781) About Me  (Show Source):
You can put this solution on YOUR website!
.

It looks like you need to learn  (to get familiar with)  the general theory/technique on solving systems of two equations in two unknown.

In this site I developed such lessons for beginner students.  These lessons are
    - Solution of the linear system of two equations in two unknowns by the Substitution method
    - Solution of the linear system of two equations in two unknowns by the Elimination method
    - Solution of the linear system of two equations in two unknowns using determinant
    - Geometric interpretation of the linear system of two equations in two unknowns
    - Useful tricks when solving systems of 2 equations in 2 unknowns by the Substitution method

They give you the general theory and a lot of examples which you can consider as your TEMPLATES.

Consider these lessons as your textbook,  your handbook,  your guide and your  (free of charge)  home teacher.

Also,  you have this free of charge online textbook in ALGEBRA-I in this site
    - ALGEBRA-I - YOUR ONLINE TEXTBOOK.

The referred lessons are the part of this online textbook under the topic "Systems of two linear equations in two unknowns".


Save the link to this online textbook together with its description

Free of charge online textbook in ALGEBRA-I
https://www.algebra.com/algebra/homework/quadratic/lessons/ALGEBRA-I-YOUR-ONLINE-TEXTBOOK.lesson

to your archive and use it when it is needed.