SOLUTION: One speed skater starts across a frozen lakebat an average speed of 8 m / s. Ten minutes later, a second skater start from the same points and skate the same direction at speed of

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Question 1199766: One speed skater starts across a frozen lakebat an average speed of 8 m / s. Ten minutes later, a second skater start from the same points and skate the same direction at speed of 9m/s. How many seconds after the 2 and skater will overtake the first skater?

Answer by greenestamps(13203) About Me  (Show Source):
You can put this solution on YOUR website!


In 10 minutes at 8 m/s, the first skater travels (10)(60)(8) = 4800 m.

The rate at which the second skater catches up to the first is the difference in their speeds, which is 1 m/s.

To make up the 4800 m at the rate of 1 m/s takes 4800/1 = 4800 seconds.

ANSWER: 4800 seconds

(notes....)
(1) That's a very long frozen lake
(2) Speed skaters don't maintain speeds like that for those amounts of time