SOLUTION: Suppose that the weight of navel oranges is normally distributed with mean 8 ounces ,and standart deviation 1.5 ounces.ıf you randomly select a navel orange ,what is the probabilt

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Question 1199705: Suppose that the weight of navel oranges is normally distributed with mean 8 ounces ,and standart deviation 1.5 ounces.ıf you randomly select a navel orange ,what is the probabilty that it weighs.
a} more than 11.5 ounces ?
b} between 6.2 and 7 ouncles?
c} ıf the randomly selected navel orange weighs more than X value has a probalitiy 89.07% find the value of X

Answer by ikleyn(52786) About Me  (Show Source):
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Suppose that the weight of navel oranges is normally distributed with mean 8 ounces,
and standart deviation 1.5 ounces. If you randomly select a navel orange,
what is the probabilty that it weighs.
a} more than 11.5 ounces ?
b} between 6.2 and 7 ouncles?
c} ıf the randomly selected navel orange weighs more than X value has a probalitiy 89.07%
find the value of X
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(a)  This probability is the area under the given specified normal curve 
     on the right of the raw mark z= 11.5 ounces.

     Use the function normalcdf on your TI calculator
          
                        z1    z2   mean   SD      <<<---=== format
         p = normalcdf(11.5, 9999,  8,    1.5) = . . . 


      For instructions on this function normalcdf, if you need them, see the link
          https://www.usu.edu/math/cfairbourn/calculatorhelps/normalcdfti-84.pdf



(b)  This probability is the area under the given specified normal curve 
     between the raw marks z= 6.2 and z= 7  ounces

     Use the function normalcdf on your TI calculator
          
                        z1    z2   mean   SD      <<<---=== format
         p = normalcdf(6.2,    7,   8,    1.5) = . . . 


      For instructions on this function normalcdf, if you need them, see the link
          https://www.usu.edu/math/cfairbourn/calculatorhelps/normalcdfti-84.pdf



(c)  This probability is the raw mark, such that the area under the specified normal curve 
     on the left of this mark is 1-0.8907 = 0.1093.

     Use the function invNormal on your TI-83 / TI-84 calculator
          
                     probability   mean   SD      <<<---=== format
         p = invNorm(0.1093,       8,    1.5) = . . . 


      For instructions on this function invNorm, if you need them, see the link
          https://www.statology.org/invnorm-ti-84/

Solved - - - you got full instruction set among with all necessary explanations.