Question 1199678: Hello,
I need help with this question. Detailed working out would be greatly appreciated.
The graph of y=f(x) has rule of the form f(x)= a(x+b)^3+2
Find the values of a and b.
The two coordinates on a graph are (1,2) and (3,6).
This is my working out so far:
f(1)=2 and f(3)=6
2=a(1+b)^3+2 (1)
6=a(3+b)^3+2 (2)
Thanks for your help.
Answer by htmentor(1343)   (Show Source):
You can put this solution on YOUR website! Let's start with your equation (1):
2 = a(1+b)^3+2
To satisfy this equation, the 1st term a(1+b)^3 must be equal to zero.
a(1+b)^3+2 = 0, which means either a=0 or (1+b)^3 = 0
If a = 0, we would have f(x) = 2 which would not satisfy the 2nd point (3,6).
(1+b)^3 = 0 -> b = -1.
Use equation (2) to solve for a:
8a + 2 = 6 -> a = 1/2
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