SOLUTION: There are 18 coins in your pocket consisting of nickels and dimes. The total value of the coins is $1.25. How many of each type of coin do you have? (Hint: the number of nickels an

Algebra ->  Customizable Word Problem Solvers  -> Numbers -> SOLUTION: There are 18 coins in your pocket consisting of nickels and dimes. The total value of the coins is $1.25. How many of each type of coin do you have? (Hint: the number of nickels an      Log On

Ad: Over 600 Algebra Word Problems at edhelper.com


   



Question 1199658: There are 18 coins in your pocket consisting of nickels and dimes. The total value of the coins is $1.25. How many of each type of coin do you have? (Hint: the number of nickels and dimes add up to 18 so if you know the number of nickels, you can subtract it from 18 to find the number of dimes).

Found 2 solutions by Edwin McCravy, josgarithmetic:
Answer by Edwin McCravy(20060) About Me  (Show Source):
You can put this solution on YOUR website!
Here's a clever way to do it. But your teacher probably won't like it:

$1.25 in all nickels would take 125/5 = 25 nickels. But since there are only
18 coins, 25-18=7 of them must be dimes.  The other 18-7=11 must be nickels.

But your teacher probably wanted you to do it this way:

Let n = the number of nickels
Then 18-n = the number of dimes

The value of the n nickels is $0.05n
The value of the 18-n dimes is $0.10(18-n)

If you add those two you must get the total amount of money.

$0.05n + $0.10(18-n) = $1.25

Take away the $'s and multiply through by 100

5n + 10(18-n) = 125

Solve that for n.  Then subtract from 18 to get the number of dimes.

Edwin


Answer by josgarithmetic(39621) About Me  (Show Source):
You can put this solution on YOUR website!
$1.25 in nickels and dimes, 18 coins

d dimes
18-d nickels
10d%2B5%2818-d%29=125

10d%2B5%2A18-5d=125
%2810-5%29d=125-5%2A18
d=%28125-5%2A18%29%2F%2810-5%29------simplify and compute.
d=%285%2A5%2A5-5%2A18%29%2F5
d=25-18
highlight%28d=7%29---------nickels=11