SOLUTION: Let's say you have 4 painters that have completed 12 rooms in 8 hours. Assuming they are working at the same efficiency, how many hours does it take 7 painters to paint 21 rooms?
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-> SOLUTION: Let's say you have 4 painters that have completed 12 rooms in 8 hours. Assuming they are working at the same efficiency, how many hours does it take 7 painters to paint 21 rooms?
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Question 1199624: Let's say you have 4 painters that have completed 12 rooms in 8 hours. Assuming they are working at the same efficiency, how many hours does it take 7 painters to paint 21 rooms?
Found 3 solutions by ikleyn, josgarithmetic, greenestamps:Answer by ikleyn(52803) (Show Source):
You can put this solution on YOUR website! .
Let's say you have 4 painters that have completed 12 rooms in 8 hours.
Assuming they are working at the same efficiency, how many hours does it take
7 painters to paint 21 rooms?
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Let the number of hours in the second scenario be h.
The rate of job of each painter in the 1st scenario is = of the room per hour.
The rate of work of each worker in the 2nd scenario is = .
The rate of work is the same in both scenario, so we can write this equation
= .
It implies h = 8 hours. ANSWER
Solved.
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You have received two responses showing very different ways to solve the problem using formal algebraic methods.
Here is a quick and easy informal method for solving the problem.
From the first scenario to the second, the number of painters increases by a factor of 7/4. Increasing the number of painters decreases the required time, so the 8 hours in the first scenario gets multiplied by 4/7 because of the increased number of workers.
From the first scenario to the second, the number of rooms to be painted increases by a factor of 21/12 = 7/4. Increasing the number of rooms increases the required time, so the 8 hours in the first scenario gets multiplied by 7/4 because of the increased number of rooms.
Combining the effects of the increased number of workers and the increased number of rooms, the 8 hours in the first scenario gets multiplied by (4/7)(7/4) = 1 -- so the time required for the second scenario is the same 8 hours.
That's a lot of words to explain a simple method for solving the problem. Without all the words, the complete path to the solution is this: