Question 1199568: Bob threw a ball upward at a velocity of 10 m/s while standing on the roof of a building that was 12 m high. What was the height of the ball after 2 seconds?
I am using h= -16t^2 +10t + 12
if I substitute 2 for t, I get -32. How can I get negative time?
Answer by htmentor(1343)   (Show Source):
You can put this solution on YOUR website! First of all, you are solving for the height of the ball, not the time.
Secondly, you are mixing English units and metric units. We are given the speed
and height in m/s and m, but in the formula h(t) = h0 + v0*t - 1/2g*t^2, you are
using g = 32 ft/s^2 instead of g = 9.8 m/s^2. Make the substitution and you will
get a sensible answer for the height.
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