SOLUTION: find the equation of a parabola with vertex on the line y=2x, axis parallel to the y axis and passing through (3/2, 1) & (3,4)

Algebra ->  Quadratic-relations-and-conic-sections -> SOLUTION: find the equation of a parabola with vertex on the line y=2x, axis parallel to the y axis and passing through (3/2, 1) & (3,4)      Log On


   



Question 1199412: find the equation of a parabola with vertex on the line y=2x, axis parallel to the y axis and passing through (3/2, 1) & (3,4)
Answer by ikleyn(52786) About Me  (Show Source):
You can put this solution on YOUR website!
.
find the equation of a parabola with vertex on the line y=2x,
axis parallel to the y axis and passing through (3/2,1) & (3,4)
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Looking at the given points, I see that when we are moving from point (3/2,1) to point (3,4),
then x-coordinate doubles, while y-coordinate quadruples.



      It leads me to the thought / (to the hypothesis) that the vertex is the point (0,0).



Indeed, then the parabola is  y = %282%2F3%29%5E2%2Ax%5E2 = %284%2F9%29x%5E2,

and all the conditions of the problem are satisfied: the vertex lies on the line y = 2x 

at (x,y) = (0,0), and the points do belong to this parabola, as you can easily check

by substituting the coordinates into the equation.

Solved.

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Notice that my solution is logically irreproachable.

        An observation leads me to a hypothesis,
        and then I check the hypothesis by direct calculations,
        confirming that all the conditions of the problem are satisfied.