Question 1199336: Hi
Town x and town y are 560km apart. At 11am a van leaves x for y travelling at a constant speed. At the same time a bus leaves x for y travelling at a constant speed. The two pass each other at 1.20pm . The average speed of the van is 60km per hour faster than the bus.
Find the vans average speed. How far is the bus from x when it passes the van.
Thanks
Found 3 solutions by josgarithmetic, ikleyn, MathTherapy: Answer by josgarithmetic(39616) (Show Source): Answer by ikleyn(52775) (Show Source):
You can put this solution on YOUR website! .
Town x and town y are 560km apart. At 11am a van leaves x for y travelling at a constant speed.
At the same time a bus leaves x for y travelling at a constant speed. The two pass each other at 1.20pm .
The average speed of the van is 60km per hour faster than the bus.
Find the vans average speed. How far is the bus from x when it passes the van.
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The problem's formulation is absurdist and incorrect.
Answer by MathTherapy(10551) (Show Source):
You can put this solution on YOUR website!
Hi
Town x and town y are 560km apart. At 11am a van leaves x for y travelling at a constant speed. At the same time a bus leaves x for y travelling at a constant speed. The two pass each other at 1.20pm . The average speed of the van is 60km per hour faster than the bus.
Find the vans average speed. How far is the bus from x when it passes the van.
Thanks
They can't PASS EACH OTHER if they leave the same location and are heading in the same direction. One must've left x heading to y,
and the other, y heading to x.
That way, van's speed would be 150 km/h, NOT 240 km/h as the other person claims.
With the van heading to y, at 150 km/h, hours after leaving x, it would've covered
This is where they pass each other, which is also the distance that the bus is, from x.
OR
Calculate the distance the bus traveled from y to the "passing" point, and then subtract that from 560 km. The result should be the same!
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