SOLUTION: The length of a rectangle is 2 cm more than 5 times its width. If the area of the rectagle is 68cm^2, find the dimensions of the rectagle to the nearest thousandth.

Algebra ->  Rectangles -> SOLUTION: The length of a rectangle is 2 cm more than 5 times its width. If the area of the rectagle is 68cm^2, find the dimensions of the rectagle to the nearest thousandth.      Log On


   

Question 119932: The length of a rectangle is 2 cm more than 5 times its width. If the area of the rectagle is 68cm^2, find the dimensions of the rectagle to the nearest thousandth.
Answer by checkley71(8403) About Me  (Show Source):
You can put this solution on YOUR website!
LENGTH=5W+2
WIDTH=W
AREA=W*L
68=W(5W+2)
68=5W^2+2W
5W^2+2W-68=0
USING THE QUADRATIC EQUATION:x+=+%28-b+%2B-+sqrt%28+b%5E2-4%2Aa%2Ac+%29%29%2F%282%2Aa%29+ WE GET:
X=(-2+-SQRT[2^2-4*5*-68])/2*5
X=(-2+-SQRT[4+1360])/10
X=(-2+-SQRT1364)/10
X=(-2+-36.932)/10
X=(-2+36.932)/10
X=34.932/10
X=3.493 ANSWER
X=(-2-36.932)/10
X=-38.932/10
X=-3.893 ANSWER.