SOLUTION: Find the largest of three consecutive integers such that twice the greatest integer is same as 12 less than 4 times the least integer.

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Question 1199287: Find the largest of three consecutive integers such that twice the greatest integer is same as 12 less than 4 times the least integer.
Answer by josgarithmetic(39621) About Me  (Show Source):
You can put this solution on YOUR website!
CONSECUTIVE integers, n and n+1 and n+2
(not the only way to choose)

2%28n%2B2%29=-12%2B4n
-
2n%2B4=4n-12
n%2B2=2n-6
8=n---------------the smaller of these three integers.

n%2B2=highlight%2810%29------the larger of the three integers

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If choosing n-1 lesser of the three integers and n+1 as greater of the three integers, then
2%28n%2B1%29=-12%2B4%28n-1%29
-
n%2B1=-6%2B2%28n-1%29
n%2B1=2n-2-6
1%2B2%2B6=n
n=9-------the middle integer

n%2B1=9%2B1=highlight%2810%29-----the greater of the three