SOLUTION: finding the x-intercepts of parabola:
y= -x^2+6x-1 please help
a. write the equation for the axis of symmetry.
b. use the equation to create a table of values for
Algebra ->
Customizable Word Problem Solvers
-> Geometry
-> SOLUTION: finding the x-intercepts of parabola:
y= -x^2+6x-1 please help
a. write the equation for the axis of symmetry.
b. use the equation to create a table of values for
Log On
Question 119926: finding the x-intercepts of parabola:
y= -x^2+6x-1 please help
a. write the equation for the axis of symmetry.
b. use the equation to create a table of values for the quadratic equation finding values of both sides of the axis of symmetry. Answer by ankor@dixie-net.com(22740) (Show Source):
You can put this solution on YOUR website! y= -x^2+6x-1 please help
:
a. write the equation for the axis of symmetry.
The axis of symmetry equation: x =
In the above equation a=-1: b=6, so we have:
x = = +3
The axis of symmetry is at x=3
:
b. use the equation to create a table of values for the quadratic equation finding values of both sides of the axis of symmetry.
:
Substitute each value for x in the equation and find y.
You table should look like this:
x | y
-------
-1|-8
0|-1
+1|+4
+2|+7
+3|+8; axis of symmetry, max value
+4|+7
+5|+4
+6|-1
:
Note the that x intercepts (where it crosses 0)
between x=0 and x=+1. And x=+5, and x=+6
:
Plot these values, a graph of this:
:
Did this help you understand this?
