SOLUTION: Hi
Bob left A at 4.20pm travelling to B which was 600km at an average speed of 108km per hour. Joe left A at 5pm at an average speed of 124km per hour. How long did joe take to ca
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Bob left A at 4.20pm travelling to B which was 600km at an average speed of 108km per hour. Joe left A at 5pm at an average speed of 124km per hour. How long did joe take to ca
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Question 1199233: Hi
Bob left A at 4.20pm travelling to B which was 600km at an average speed of 108km per hour. Joe left A at 5pm at an average speed of 124km per hour. How long did joe take to catch up with Bob.
Thanks Found 4 solutions by math_tutor2020, MathTherapy, josgarithmetic, ikleyn:Answer by math_tutor2020(3817) (Show Source):
x = time Joe has been on the road
x+(2/3) = time Bob has been on the road
Time values are in hours
Let's set up Joe's equation
distance = rate*time
distance = 124*x
And do the same for Bob
distance = rate*time
distance = 108(x+2/3)
distance = 108x+108*(2/3)
distance = 108x+72
Each distance is in kilometers.
The two men will meet when they travel the same distance.
Bob's distance = Joe's distance
108x+72 = 124x
72 = 124x-108x
72 = 16x
x = 72/16
x = 4.5
That's one possible way to write the final answer
We can do a conversion like this
4.5 hours = 4 hr + 0.5 hr
4.5 hours = 4 hr + (60*0.5) min
4.5 hours = 4 hr + 30 min
or
4.5 hours = (60*4.5) min
4.5 hours = 270 min
There are a few ways you can express the answer.
Extra info:
5:00 PM + (4 hr + 30 min) = 5:00 PM + 4:30 = 9:30 PM
Joe will meet with Bob at 9:30 PM
You can put this solution on YOUR website! Hi
Bob left A at 4.20pm travelling to B which was 600km at an average speed of 108km per hour. Joe left A at 5pm at an average speed of 124km per hour. How long did joe take to catch up with Bob.
Thanks
Let time Joe takes to catch up to Bob be T
Then time Bob takes to get to the catch-up point =
We then get the following DISTANCE equation:
Time Joe takes to catch up to Bob, or
The 600 km mentioned had absolutely NIL to do with the solution to this problem. It's possible that it could've been mentioned
in order to distract/confuse the reader! Who knows!!
You can put this solution on YOUR website! Two-thirds of an hour, the amount of time Bob had traveled before Joe started to travel.
Amount of Bob's distance in this two-thirds hour: kilometers.
Joe's approach speed to Bob, kph.
How much time for Joe to catchup to Bob? , to close the 72 kilometer distance, x amount of hours; , four hours thirty minutes
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