SOLUTION: Find a model for simple harmonic motion that has an initial displacement (t=0) of 5 inches, an amplitude of 5 inches, and a frequency of 4/3 cycles per second.
The correct ans
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The correct ans
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Question 1199100: Find a model for simple harmonic motion that has an initial displacement (t=0) of 5 inches, an amplitude of 5 inches, and a frequency of 4/3 cycles per second.
The correct answer is one of the following. Which one is correct?
A) d=5cos[(8pi/3)(t)]
B) d=5sin[(8pi/3)(t)]
C) d=5cos[(3pi/8)(t)]
D) d=5sin[(3pi/8)(t)] Answer by htmentor(1343) (Show Source):
You can put this solution on YOUR website! The initial displacement at t = 0 is non-zero, thus the model must
use a cosine function. If the frequency is 4/3 cycles per sec, and 1 cycle
is 2*pi, the angular frequency is 8*pi/3. The general form of the function is:
d(t) = A*cos(w*t) there A = the amplitude and w = the angular frequency.
For this case A = 5 and w = 8*pi/3, so the answer is A).
The graph is below:
