SOLUTION: A hand of 13 cards is dealt from a standard deck of 52 cards. What is the probability that it contains more aces than tens? How does this probability change when you have the infor

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Question 1199040: A hand of 13 cards is dealt from a standard deck of 52 cards. What is the probability that it contains more aces than tens? How does this probability change when you have the information that the hand contains at least one ace?
Please I do not understand mccravy's solutions so help me with a different or more explanatory solution.
Answer by math_helper(2461) About Me  (Show Source):
You can put this solution on YOUR website!


He has given you a table of probabilities that list all the cases where the number of aces is greater than the number of tens.  You simply need to fill out the table then add up the probabilities.



Just in case:

nCr = n! / ((n-r)!r!)     

k! = k(k-1)(k-2) ... (3)(2)(1)



Example:  4C2 = 4!/((4-2)!2!) = (4*3*2)/(2*2) = 6

          4C3 = 4!/(1!*3!) = (4*3*2)/(3*2) = 4

     etc.