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Question 1198854: Quiboy can clean the barn in 6 hours, and Quiboy and Rod together can clean the same barn in 3 hours. How long would it take for Rod to clean the barn by himself?
Found 4 solutions by ikleyn, greenestamps, math_tutor2020, MathTherapy: Answer by ikleyn(52848) (Show Source): Answer by greenestamps(13203) (Show Source):
You can put this solution on YOUR website!
Tutor @ikleyn has provided a typical formal algebraic solution.
Without algebra, it might make sense to you that, since the two together take half as much time as Quiboy alone, it would also take Rod the same 6 hours to do the job alone.
If it is hard for you to see that solution using logical reasoning, here is another method for solving the problem.
In 6 hours, Quiboy can do the job alone.
In those same 6 hours, the two of them together could do the job twice, because it takes them 3 hours to do the job once.
So in 6 hours Quiboy could do the job 1 time, while in 6 hours the two together could do the job twice; that means in those same 6 hours Rod could do the job once.
ANSWER: Rod alone would take 6 hours to clean the barn alone.
Answer by math_tutor2020(3817) (Show Source):
You can put this solution on YOUR website!
The jump from 6 hours to 3 hours is "times 1/2".
This strongly suggests the two people work at the same rate, and take the same amount of time.
This is because they split the work in half (thereby cutting their worktime in half as well).
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We can think of it like saying the task is to move 60 bales of hay.
Quiboy needs 6 hours to do the job by himself.
His unit rate is 60/6 = 10 bales per hour.
When working together, the two men can do the job in 3 hours.
Their combined rate is 60/3 = 20 bales per hour.
This of course assumes neither worker hinders the other.
Quiboy offers 10 bales per hour, and the total combined rate is 20 bales per hour.
Rod offers the remaining 20-10 = 10 bales per hour.
His rate is the same as Quiboy. So he takes the same amount of time.
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If you wish to use algebra, then,
x = time (in hours) needed for Rod to do the job alone
1/6 = Quiboy's unit rate
1/x = Rod's unit rate
1/3 = combined unit rate
1/6 + 1/x = 1/3
x/(6x) + 6/(6x) = 1/3
(x+6)/(6x) = 1/3
3(x+6) = 6x*1
3x+18 = 6x
18 = 6x-3x
18 = 3x
3x = 18
x = 18/3
x = 6
Or you could say
1/6 + 1/x = 1/3
6x * ( 1/6+1/x ) = 6x*( 1/3 )
6x*(1/6) + 6x*(1/x) = 6x*( 1/3 )
x + 6 = 2x
6 = 2x-x
6 = x
x = 6
In my opinion an algebraic approach is a bit overkill.
Despite that, it's still handy to know this pathway and get practice.
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Answer: 6 hours
Answer by MathTherapy(10555) (Show Source):
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