SOLUTION: A training field is formed by joining a rectangle and two semicircles, as shown below. The rectangle is 97m long and 67m wide. What is the length of a training track running around

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Question 1198766: A training field is formed by joining a rectangle and two semicircles, as shown below. The rectangle is 97m long and 67m wide. What is the length of a training track running around the field?
Found 2 solutions by ikleyn, math_tutor2020:
Answer by ikleyn(52781) About Me  (Show Source):
You can put this solution on YOUR website!
.
A training field is formed by joining a rectangle and two semicircles, as shown below.
The rectangle is 97m long and 67m wide. What is the length of a training track running around the field?
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Nothing is shown below.

I really do not understand, for what reason do you pronounce/print these words,
if you do not keep your promising.


I simply suspect that you do not read what you copy-paste-submit.



Answer by math_tutor2020(3817) About Me  (Show Source):
You can put this solution on YOUR website!

It depends if the diagram is this


OR if it's this



If it's the first diagram, then the semicircular portions can be joined together to form a circle of diameter 67 meters.
The circumference would be C = pi*d = 3.14*67 = 210.38 meters approximately.
This would be the distance along the curved portion of the track.
The straight line portions (two copies of 97) are added to get 210.38+97+97 = 404.38

So if your diagram is the first one I've shown above, then the answer is roughly 404.38 meters.
I used the approximation pi = 3.14; use more decimal digits of pi to get a more accurate answer.

If on the other hand the diagram was the second one I've shown above, then you'll have the two semicircular portions combine to a circle of diameter 97 meters.
C = pi*d = 3.14*97 = 304.58 is the curved portion of the track.
304.58+67+67 = 438.58 is the total perimeter.


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Summary:
404.38 meters is the approximate perimeter for the first diagram
438.58 meters is the approximate perimeter for the second diagram
Both approximations are based on pi = 3.14