SOLUTION: the average of four number is 40. the third number is 12 more than the second, the fourth is 8 less than the first. find the number?

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Question 1198655: the average of four number is 40. the third number is 12 more than the second, the fourth is 8 less than the first. find the number?
Found 2 solutions by Alan3354, greenestamps:
Answer by Alan3354(69443) About Me  (Show Source):
You can put this solution on YOUR website!
the average of four number is 40. the third number is 12 more than the second, the fourth is 8 less than the first. find the number?
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The sum of the numbers is 4*40 = 160
1st # is f, then s, then t, then h
f + s + t + h = 160
t = s+12
h = f-8
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f + s + s+12 + f-8 = 160
2f + 2s + 4 = 160
f + s = 78
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This is not sufficient info.

Answer by greenestamps(13203) About Me  (Show Source):
You can put this solution on YOUR website!


The question says "Find the number."

WHICH number?

And, as the other tutor says, the given information is not enough to find ANY of the numbers.

Re-post the problem correctly....