SOLUTION: I tried graphing this and i got only one curve. Since the first exponent is 4 I assumed that there should be four curves. I used an X/Y chart to graph and checked my answers multip

Algebra ->  Quadratic-relations-and-conic-sections -> SOLUTION: I tried graphing this and i got only one curve. Since the first exponent is 4 I assumed that there should be four curves. I used an X/Y chart to graph and checked my answers multip      Log On


   

Question 119846This question is from textbook Algebra 2
: I tried graphing this and i got only one curve. Since the first exponent is 4 I assumed that there should be four curves. I used an X/Y chart to graph and checked my answers multiple times. What am i doing wrong? Please help me.
2x%5E4-4x%5E3-2x%5E2%2B3x-5 This question is from textbook Algebra 2

Found 2 solutions by jim_thompson5910, josmiceli:
Answer by jim_thompson5910(35256) About Me  (Show Source):
You can put this solution on YOUR website!
What's most likely happening is your window is only allowing you to look at only a piece/branch of the curve.


Try this window and you should be able to get a better look
X-min: -12
X-max: 12
Y-min: -10
Y-max: 10

Answer by josmiceli(19441) About Me  (Show Source):
You can put this solution on YOUR website!
This equation has 4 roots, so it crosses the x-axis 4 times if
they are all real roots, Here is the graph
+graph%28+600%2C+600%2C+-8%2C+8%2C+-30%2C+30%2C+2x%5E4+-+4x%5E3+-+2x%5E2+%2B+3x+-+5%29+
Looking at the plot, there are 2 x-axis crossings, so there are 2 real roots
and 2 imaginary roots