SOLUTION: simbi and ibukun shared some sweets in the ratio of 3:7 simbi got 60 sweets what was ibukun share?

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Question 1198411: simbi and ibukun shared some sweets in the ratio of 3:7 simbi got 60 sweets what was ibukun share?
Found 2 solutions by ikleyn, MathTherapy:
Answer by ikleyn(52802) About Me  (Show Source):
You can put this solution on YOUR website!
.

The sweets that they share are 3x and 7x, with x as the common measure.


We are given that 3x = 60;  hence,  x = 60/3 = 20.


ANSWER.  Simbi has 60 sweets (we just know it from the problem);

         Ibukun has 20*7 = 140 sweets (it is what we just determined).

Solved.



Answer by MathTherapy(10552) About Me  (Show Source):
You can put this solution on YOUR website!

simbi and ibukun shared some sweets in the ratio of 3:7 simbi got 60 sweets what was ibukun share?
Fracton Simbi rec'd: matrix%281%2C5%2C+3%2F%283+%2B+7%29%2C+%22=%22%2C+3%2F10%2C+or%2C+.3%29
Fracton Ibukun rec'd: matrix%281%2C7%2C+7%2F%283+%2B+7%29%2C+or%2C+1+-+3%2F10%2C+%22=%22%2C+7%2F10%2C+or%2C+.7%29
With Simbi receiving 60 sweets, we get the following PROPORTION: matrix%281%2C3%2C+.3%2F.7%2C+%22=%22%2C+60%2FI%29 with I being amount Ibukun rec'd
                                                                 .3I = .7(60) ---- Cross-multiplying
                                          Amount Ibukun rec'd, or