Question 119834This question is from textbook algebra 1 for christian schools
: 3. Lynn has $8.58 in quarters and pennies. If she has eight times as many pennies as quarters, how many of each does she have?
This question is from textbook algebra 1 for christian schools
Answer by ankor@dixie-net.com(22740)   (Show Source):
You can put this solution on YOUR website!
Write a simple equation for each statement, c = no. of pennies; q = no. of quarters
:
"Lynn has $8.58 in quarters and pennies."
.01c + .25q = 8.58
:
"If she has eight times as many pennies as quarters,"
c = 8q
:
how many of each does she have?
:
Substitute 8q for c in the 1st equation, find q:
.01(8q) + .25q = 8.58
.08q + .25q = 8.58
.33q = 8.58
q = 8.58/.33
q = 26 quarters
then
8 * 26 = 208 pennies
:
:
Check solution:
.01(208) + .25(26) =
2.08 + 6.50 = 8.58; confirms our solution
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