SOLUTION: Sociologists say that 80% of married women claim that their husband’s mother is the biggest bone of contention in their marriages. Suppose that 5 married women are having coffe

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Question 1198224: Sociologists say that 80% of married women claim that their husband’s mother is the biggest bone of contention in their marriages. Suppose that 5 married women are having coffe together one morning. What is the probability that :
1 exactly 3 of then dislike their mother- in law ?
2 all of them dislike their mother- in law ?
3 none of them dislike their mother -in law?
4 at least 4 of them dislike their mother in law?
5 no more than 3 of them dislike their mother in law ?
7 what is the expected number of women who dislike their mother in law ? What is the standard deviation of the distribution?

Answer by ikleyn(52803) About Me  (Show Source):
You can put this solution on YOUR website!
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Sociologists say that 80% of married women claim that their husband’s mother
is the biggest bone of contention in their marriages.
Suppose that 5 married women are having coffe together one morning.
What is the probability that :
(1) exactly 3 of then dislike their mother- in law ?
(2) all of them dislike their mother- in law ?
(3) none of them dislike their mother -in law?
(4) at least 4 of them dislike their mother in law?
(5) no more than 3 of them dislike their mother in law ?
(7) what is the expected number of women who dislike their mother in law ?
What is the standard deviation of the distribution?
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It is a binomial distribution probability problem.


To facilitate my calculations, I will use an appropriate online (free of charge) calculator 
at this web-site 

https://stattrek.com/online-calculator/binomial.aspx


It provides a convenient input (and output) for all relevant options/cases.


(1)  exactly 3 of them dislike their mother-in-law ?

         - number of trials        n = 5;
         - number of success trial k = 3;
         - Probability of success on a single trial p = 0.8.

           P(n=5; k=3; p=0.8) = 0.2048  (rounded).      ANSWER


(2)  all of them dislike their mother-in law?

         - number of trials        n = 5;
         - number of success trial k = 5;
         - Probability of success on a single trial p = 0.8.

           P(n=5; k=5; p=0.8) = 0.3277  (rounded).     ANSWER


(3)  none of them dislike their mother-in-law?

         - number of trials        n = 5;
         - number of success trial k = 0;
         - Probability of success on a single trial p = 0.8.

           P(n=5; k=0; p=0.8) = 0.00032.     ANSWER


(4)  at least 4 of them dislike their mother-in-law?

         - number of trials        n = 5;
         - number of success trial k >= 4;
         - Probability of success on a single trial p = 0.8.

           P(n=5; k>=4; p=0.8) = 0.7373  (rounded).    ANSWER


(5) no more than 3 of them dislike their mother-in-law?

         - number of trials        n = 5;
         - number of success trial k <= 3;
         - Probability of success on a single trial p = 0.8.

           P(n=5; k<=3; p=0.8) = 0.2627  (rounded).     ANSWER


(7)  The expected number of this binomial distribution is n*p = 5*0.8 = 4.

     The standard deviation is  s = sqrt%28p%2An%2A%281-p%29%29 = sqrt%280.8%2A5%2A%281-0.8%29%29 = 0.8944  (rounded).

Solved.

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Do not think that this problem is very original. Similar problems come often to this forum.

See, for example, this link

https://www.algebra.com/algebra/homework/Probability-and-statistics/Probability-and-statistics.faq.question.1160081.html

(it came couple of years ago . . . )