Question 1198207: The price of a bond, A(x), over a 12-month period decreased according to the equation A(x) =-0.75x2 - 6x + 20, where x equals the number of months from the beginning of the period. The price of another bond, B(x), increased according to the
equation B(x) = 3x + 1.50 over the same 12-month period. Determine approximately how
many months it took for both bond prices to be the same?
Found 2 solutions by ewatrrr, ikleyn:
Answer by ewatrrr(24785)   (Show Source):
You can put this solution on YOUR website! -0.75x^2 - 6x + 20 = 3x + 1.50
-0.75x^2 - 9x + 18.50 = 0
Using Handheld TI or similarly an inexpensive calculator like an Casio fx-115 ES plus
Disregarding negative value
x = 1.789 rounded
0r approximately, it took 2 months for both bond prices to be the same
Answer by ikleyn(52914)  (Show Source):
You can put this solution on YOUR website! .
For your info:
The price of a bond, A(x), becomes negative starting from the 3-rd months,
so it makes no much sense to speak about the price of A(x) over a 12-months period.
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