SOLUTION: A ball is thrown upward. The path of the ball is modelled by the equation: h=-4.9t^2 + 9.9t + 1, where h is the height of the ball above the ground (in meters) and t is time (in se
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-> SOLUTION: A ball is thrown upward. The path of the ball is modelled by the equation: h=-4.9t^2 + 9.9t + 1, where h is the height of the ball above the ground (in meters) and t is time (in se
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Question 1198104: A ball is thrown upward. The path of the ball is modelled by the equation: h=-4.9t^2 + 9.9t + 1, where h is the height of the ball above the ground (in meters) and t is time (in seconds).
Time (s) Height (m)
0.0
0.5
1.0
1.5
2.0
2.5
3.0
a) How long will it take the ball to reach the maximum height?
You can put this solution on YOUR website! A ball is thrown upward. The path of the ball is modelled by the equation: h=-4.9t^2 + 9.9t + 1, where h is the height of the ball above the ground (in meters) and t is time (in seconds).
Time (s) Height (m)
0.0
0.5
1.0
1.5
2.0
2.5
3.0
a) How long will it take the ball to reach the maximum height?
It's a parabola.
The vertex, max height, is at t = -b/2a
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b) After how many seconds will the ball land?
When h=-4.9t^2 + 9.9t + 1 = 0
