SOLUTION: One 1700-pound load of feed mixture contains 25% corn, 40% bran, and roughage. How many pounds of corn should be added to a load of feed mixture to make the feed 40% corn?
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Question 1198048: One 1700-pound load of feed mixture contains 25% corn, 40% bran, and roughage. How many pounds of corn should be added to a load of feed mixture to make the feed 40% corn? Found 3 solutions by ikleyn, josgarithmetic, greenestamps:Answer by ikleyn(52788) (Show Source):
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One 1700-pound load of feed mixture contains 25% corn, 40% bran, and roughage.
How many pounds of corn should be added to a load of feed mixture to make the feed 40% corn?
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Let x be the mass of the corn to add, in pounds.
Then you have this equation
0.25*1700 + x = 0.4*(1700+x)
saying that the final mixture is 40% of corn.
From the equation
0.25*1700 + x = 0.4*1700 + 0.4x
x - 0.4x = 0.4*1700 - 0.25*1700
0.6x = 255
x = 255/0.6 = 425.
ANSWER. 425 pounds of the corn should be added.