SOLUTION: Hi 3/4 of the boys are equal to 1/3 of the girls. What fraction of the pupils are boys. My son son 9/13 textbook solution is 4/13. Who is correct. Thanks

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Question 1197952: Hi
3/4 of the boys are equal to 1/3 of the girls. What fraction of the pupils are boys. My son son 9/13 textbook solution is 4/13. Who is correct.
Thanks

Found 5 solutions by math_tutor2020, greenestamps, MathTherapy, josgarithmetic, ikleyn:
Answer by math_tutor2020(3817) About Me  (Show Source):
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b = number of boys
g = number of girls
b+g = number of pupils

3/4 of the [number of] boys = 1/3 of the [number of] girls
(3/4)b = (1/3)g
12*(3/4)b = 12*(1/3)g
9b = 4g
9b/g = 4
b/g = 4/9
g/b = 9/4

k = fraction of the pupils that are boys
(number of boys)/(number of pupils) = k
b/(b+g) = k
(b+g)/b = 1/k
b/b + g/b = 1/k
1 + g/b = 1/k
1 + 9/4 = 1/k .... plug in g/b = 9/4
4/4 + 9/4 = 1/k
(4+9)/4 = 1/k
13/4 = 1/k
4/13 = k
k = 4/13

Answer: 4/13 of the pupils are boys.

Side note: 9/13 is the fraction of girls (since 4/13+9/13 = 1)


Answer by greenestamps(13200) About Me  (Show Source):
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For a preliminary analysis using logical reasoning, note that it takes nearly all of the boys to equal less than half of the girls; that means the number of girls is greater.

The other tutor showed a good algebraic solution. Here is a very different solution, using only logical reasoning and basic arithmetic.

Since 3/4 of the number of boys is equal to 1/3 the number of girls, this is one of those strange problems where we want to express those two fractions with like NUMERATORS.

1/3 = 3/9, so 3/4 of the boys is equal to 3/9 of the girls. Then, with the numerators being equal, that says that there are 4 boys for every 9 girls.

So 4/13 of the students are boys and 9/13 of them are girls.


Answer by MathTherapy(10552) About Me  (Show Source):
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Hi
3/4 of the boys are equal to 1/3 of the girls. What fraction of the pupils are boys. My son son 9/13 textbook solution is 4/13. Who is correct.
Thanks
Let number of boys be B, and girls, G
We then get: matrix%282%2C3%2C+%283%2F4%29B%2C+%22=%22%2C+%281%2F3%29G%2C+3B%2F4%2C+%22=%22%2C+G%2F3%29
                 9B = 4G ------ Cross-multiplying
                matrix%281%2C3%2C+9B%2F4%2C+%22=%22%2C+G%29
Total students: # of boys + # of girls = matrix%281%2C5%2C+B+%2B+9B%2F4%2C+%22=%22%2C+4B%2F4+%2B+9B%2F4%2C+%22=%22%2C+13B%2F4%29
    Fraction of students that are boys: 

Answer by josgarithmetic(39620) About Me  (Show Source):
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x girls, y boys
3y%2F4=x%2F3

-

y%283%2F4%29=x%281%2F3%29
y%2Fx=%281%2F3%29%2F%283%2F4%29
y%2Fx=4%2F9

4 parts of the group boys
9 parts of the group girls
total 13 parts

The FRACTION which are boys,
4%2F13

Answer by ikleyn(52798) About Me  (Show Source):
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.

They want you determine  b%2F%28g%2Bb%29.


So you write  b%2F%28g%2Bb%29 = %28%283%2F4%29%2Ab%29%2F%28%283%2F4%29%2A%28g%2Bb%29%29 = %28%281%2F3%29%2Ag%29%2F%28%283%2F4%29g%2B%283%2F4%29b%29 = %28%281%2F3%29%2Ag%29%2F%28%283%2F4%29%2Ag%2B%281%2F3%29%2Ag%29 = %28%281%2F3%29%29%2F%283%2F4%2B1%2F3%29 = %28%281%2F3%29%29%2F%289%2F12%2B4%2F12%29 = %28%281%2F3%29%29%2F%28%2813%2F12%29%29 = 12%2F%283%2A13%29 = 4%2F13.    ANSWER

Solved.