SOLUTION: A population of bacteria is growing according to the equation
P(t)=1950e^0.07t. Estimate when the population will exceed 3010.
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-> SOLUTION: A population of bacteria is growing according to the equation
P(t)=1950e^0.07t. Estimate when the population will exceed 3010.
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Question 1197950: A population of bacteria is growing according to the equation
P(t)=1950e^0.07t. Estimate when the population will exceed 3010. Answer by ikleyn(52803) (Show Source):
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A population of bacteria is growing according to the equation
P(t)=1950e^0.07t. Estimate when the population will exceed 3010.
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Write inequality
3010 < .
Divide both sides by 1950
< ,
which is the same as
< .
Take logarithm base 10 of both sides
log(1.543589744) < 0.07*t.
Express t and calculate
t > = 2.693312634.
Round with 4 decimals t = 2.6933. ANSWER
The problem does not provide the name of the time units,
so I can not name the unit of the time in my answer.
Solved.
What you see in my post, is a standard procedure for solving such problems.
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To see many other similar and different solved problems on bacteria growth, look into the lesson
- Bacteria growth problems
in this site.
