SOLUTION: Crew A can assemble 2 cars in 5 days, and crew B can assemble 3 cars in 7 days. If both crews together assemble 100 cars, with crew B working 10 days longer than crew A, how many

Algebra ->  Linear-equations -> SOLUTION: Crew A can assemble 2 cars in 5 days, and crew B can assemble 3 cars in 7 days. If both crews together assemble 100 cars, with crew B working 10 days longer than crew A, how many       Log On


   

Question 1197850: Crew A can assemble 2 cars in 5 days, and crew B can assemble 3 cars in 7 days. If both crews
together assemble 100 cars, with crew B working 10 days longer than crew A, how many days
(rounded to the nearest day) must each crew work?
Answer by josgarithmetic(39617) About Me  (Show Source):
You can put this solution on YOUR website!
CREW        RATE         
A           2/5           
B           3/7           
A and B    29/35

Combined Rate A and B
2%2F5%2B3%2F7
14%2F35%2B15%2F35
29%2F35
B worked 10 hours longer than both crews combined.
The two crews made 100 cars.

Time for B alone to finish, x+10
Time A and B together, x
highlight_green%28%2829%2F35%29x%2B%283%2F7%29%2A10=100%29---- B worked 10 hours beyond A.
unfinished --
x=115.5 days
seems strange