SOLUTION: Write the complex number of square root of 3 + i

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Question 1197765: Write the complex number of square root of 3 + i
Answer by math_helper(2461) About Me  (Show Source):
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+a+%2B+b%2Ai+ can be written +m+theta+ ("m angle theta"),
where:
m = +sqrt%28a%5E2+%2B+b%5E2%29+
and
+theta = +tan%5E-1+%28+b%2F+a%29+

For 3+i: m = +sqrt%283%5E2+%2B+1%5E2%29+ = +sqrt%2810%29+
theta = tan%5E-1%281%2F3%29+ or approx. 18.435 degrees.
Now, to find the square root, just take the square root of m and divide the angle +theta by two:

sqrt(3+i) = +root%284%2C10%29++%281%2F2%29%2A+18.435%5Eo+
or approx. = +1.778++9.218%5Eo+
If you must express this as 'a + bi' form (rectangular form):
a = m * cos(theta) = 1.778*cos(9.218) = 1.755
b = m * sin(theta) = 1.778*sin(9.218) = 0.285
so +sqrt%283%2Bi%29++highlight%281.755+%2B+0.285i%29+

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EDIT: the notation I used really comes from Electrical Engineering, but keep in mind it is just shorthand for a+bi = m%2Ae%5E%28i%2Atheta%29+