SOLUTION: suppose two trains leave a station at the same time, traveling in opposite directions. Train B travels 20 mph faster than Train A. In 4.5 hours, the trains are 459 miles apart. Fin

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Question 1197739: suppose two trains leave a station at the same time, traveling in opposite directions. Train B travels 20 mph faster than Train A. In 4.5 hours, the trains are 459 miles apart. Find the speed of each train.
Answer by ikleyn(52776) About Me  (Show Source):
You can put this solution on YOUR website!
.

x mph      = speed of the slower train.

(x+20) mph = speed of the faster train.


Total distance equation

    4.5x + 4.5(x+20) = 459.


Divide both sides by 4.5

    x + (x+20) = 102

      2x       = 102 - 20 = 82

       x                  = 82/2 = 41.


ANSWER.  The speed of the slower train is 41 mph.  That of the faster train is 41+20 = 61 mph.

Solved.

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    - Travel and Distance problems for two bodies moving in opposite directions
    - Travel and Distance problems for two bodies moving in the same direction (catching up)
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