SOLUTION: 2) The sum of the digits of a two- digit counting number is 6. When the digits are reversed, the number is 18 greater than the original number. What was the original number?

Algebra ->  Test -> SOLUTION: 2) The sum of the digits of a two- digit counting number is 6. When the digits are reversed, the number is 18 greater than the original number. What was the original number?       Log On


   



Question 1197732: 2) The sum of the digits of a two- digit counting number is 6. When the digits are reversed, the number is 18 greater than the original number. What was the original number?
Found 3 solutions by ikleyn, josgarithmetic, greenestamps:
Answer by ikleyn(52817) About Me  (Show Source):
You can put this solution on YOUR website!
.
The sum of the digits of a two- digit counting number is 6.
When the digits are reversed, the number is 18 greater than the original number.
What was the original number?
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Let the digits of the original number be "a" and "b", reading from left to right.


Then the number is 10a+b,  and we are given thast 

    a + b = 6.    (1)


The reversed number in written form is  "ba" :  its value is  10b+a.


So, we have second equation

    (10b+a) - (10a+b) = 18,

or

    9b - 9a = 18

    9(b-a)  = 18

     b - a  = 2.    (2)


Thus you have two equations, (1) and (2), to find "a" and "b".

To do it, express  b = 6-a  from (1) and substitute into (2).  You will get

    (6-a) - a = 2

     6 - 2a   = 2

     6 - 2    = 2a

       4      = 2a

       a      = 4/2 = 2.


Thus you found  a= 2,  b= 6-a = 6-2= 4.


Hence, the original number is  24.    ANSWER

Solved, with full explanations.



Answer by josgarithmetic(39621) About Me  (Show Source):
You can put this solution on YOUR website!
Number, 10t%2Bu

system%28t%2Bu=6%2C10u%2Bt=18%2B10t%2Bu%29

system%28t%2Bu=6%2C9u-9t=18%29

system%28t%2Bu=6%2Cu-t=2%29

system%28u%2Bt=6%2Cu-t=2%29
May be able to see without making steps on paper,
u=4 and t=2;

The two-digit number, 24.

Answer by greenestamps(13203) About Me  (Show Source):
You can put this solution on YOUR website!


The responses from the other tutors show good formal algebraic solutions.

If a formal algebraic solution is not required and the speed of solving the problem is important (as on a timed competitive test), then this kind of problem can be solved quickly using this fact:

The difference between a 2-digit number and the 2-digit number with the digits reversed is 9 times the difference of the digits.

It is easy to show this. If t and u are the tens and units digits of the original number, then the original number is 10t+u and the number with the digits reversed is 10u+t. The difference between the two 2-digit numbers is

(10t+u)-(10u+t)=9t-9u=9(t-u)

So in this problem, with a difference of 18 between the two 2-digit numbers, we know the sum of the digits is 6 and the difference is 2. Logical reasoning and/or simple arithmetic or algebra shows us the two digits are 2 and 4.

Then, since the number with the digits reversed is larger, the original number is 24.