SOLUTION: 1) Reds varied directly as blues squared and inversely as green. When there were 160 reds, there were 4 blues and 2 greens. How many reds were there when there were 7 blues and 10
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Question 1197731: 1) Reds varied directly as blues squared and inversely as green. When there were 160 reds, there were 4 blues and 2 greens. How many reds were there when there were 7 blues and 10 greens? Found 2 solutions by josgarithmetic, greenestamps:Answer by josgarithmetic(39620) (Show Source):
If you are developing a formula for the number of reds as a function of the numbers of blues and greens, to be used repeatedly in a large number of problems like this, then you want to find the constant of variation, as the other tutor did.
But taking the time to do that is a waste of time when you are only solving a single problem like the given one.
The given number of reds is 160.
The number of reds varies directly as the square of the number of blues. The number of blues changes by a factor of 7/4, so the number of reds changes by a factor of (7/4)^2 = 49/16.
The number of reds varies inversely as the number of greens. The number of greens changes by a factor of 10/2 = 5, so the number of reds changes by a factor of (1/5).
The number of reds when there are 7 blues and 10 greens is
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