Question 1197697: Compute the odds in favor of obtaining at least 1 head when a single coin is tossed 6 times. Found 2 solutions by MathLover1, ikleyn:Answer by MathLover1(20849) (Show Source):
You can put this solution on YOUR website!
If you think of the tosses as a sequence of flips, there are total possibilities.
There is only way to get all heads, so the probability of getting all heads is .
To get the probability of getting at , this is the opposite of the probability of getting - i.e. all tails.
The probability of getting all tails is .
To get the probability of getting at , we subtract this from to get:
You can put this solution on YOUR website! .
Compute the odds in favor of obtaining at least 1 head when a single coin is tossed 6 times.
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In terms of probabilities
P(at least 1 head when a single coin is tossed 6 times) =
= 1 - P(no head when a single coin is tossed 6 times) = 1 - = 1 - = .
Hence, in terms of odds, the odds in favor of obtaining at least 1 head when a single coin
is tossed 6 times are 63 against 1. ANSWER
Solved.
In simple words, the space of events consists of 64 elements; of them, 63 are favorable, 1 is not.
