Question 1197611: If 0 < x < pi/4 is such that cscx - secx = (13^1/2)/6, then cotx - tanx equals
Found 2 solutions by ewatrrr, math_tutor2020: Answer by ewatrrr(24785) (Show Source): Answer by math_tutor2020(3817) (Show Source):
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The goal is to find the value of based on and the restriction
Note:
Let's simplify a bit like shown below
You'll need a list of trig identities such as this here
https://tutorial.math.lamar.edu/pdf/Trig_Cheat_Sheet.pdf
In short, is the same as
is an identity.
Keep this in mind for later.
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Now let's solve for x in
Squaring both sides
Let w = sin(2x)
Let's solve for w.

Use the quadratic formula (I'll skip showing the steps) to find that the two roots for w are
w = -12 or w = 12/13
We're told that
0 < x < pi/4
Multiply each side by 2
2*0 < 2x < 2*pi/4
0 < 2x < pi/2
Then apply sine to each
sin(0) < sin(2x) < sin(pi/2)
0 < sin(2x) < 1
This shows that the output of sin(2x) must be between 0 and 1, which rules out w = -12 aka sin(2x) = -12
Also, the range of sin(x) is . So even if we didn't have to worry about 0 < x < pi/4, it's still impossible to have sin(2x) = -12 (not unless we want to involve complex numbers, but we'll stay in the real number set).
We'll ignore w = -12 and go for w = 12/13 only.
Therefore, sin(2x) = 12/13
Isolating x gets us x = 0.5*arcsin(12/13)
There are infinitely many solutions to sin(2x) = 12/13, but again we focus on the interval 0 < x < pi/4, which means we only have one solution.
Note: arcsine is the same as inverse sine aka
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Recall the ultimate goal is to find which we found was equivalent to
Plug in x = 0.5*arcsin(12/13) and simplify
The question now is: how can we evaluate cot(arcsin(12/13))?
Let theta = arcsin(12/13) which rearranges to sin(theta) = 12/13
Since sine = opposite/hypotenuse, this gives us a right triangle with opposite leg 12 and hypotenuse 13.
Use the pythagorean theorem to find the adjacent leg is 5 units.
We have a 5-12-13 right triangle (this is one of the infinitely many pythagorean triples).

Tangent is the ratio of opposite/adjacent
the reciprocal is cotangent which is adjacent/opposite
So cot(theta) = adjacent/opposite = 5/12
which means,
Therefore,

when and
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Answer: 5/6
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