| 
 
 
| Question 1197611:  If 0 < x < pi/4 is such that cscx - secx = (13^1/2)/6, then cotx - tanx equals
 Found 2 solutions by  ewatrrr, math_tutor2020:
 Answer by ewatrrr(24785)
      (Show Source): Answer by math_tutor2020(3817)
      (Show Source): 
You can put this solution on YOUR website! The goal is to find the value of
  based on  and the restriction   
 Note:
   
 Let's simplify
  a bit like shown below You'll need a list of trig identities such as this here
 https://tutorial.math.lamar.edu/pdf/Trig_Cheat_Sheet.pdf
 
   
 
   
 
   
 
   
 
   
 
   
 
 In short,
  is the same as   
 
  is an identity. Keep this in mind for later.
 
 ----------------------------------------------------------
 
 Now let's solve for x in
   
 
   
 
   
 
   
 
   
 
   
 
   
 
  Squaring both sides 
 
   
 
   
 
   
 
  Let w = sin(2x) 
 Let's solve for w.
 
   
 
   
 
   
 
  Use the quadratic formula (I'll skip showing the steps) to find that the two roots for w are
 w = -12 or w = 12/13
 
 We're told that
 0 < x < pi/4
 Multiply each side by 2
 2*0 < 2x < 2*pi/4
 0 < 2x < pi/2
 Then apply sine to each
 sin(0) < sin(2x) < sin(pi/2)
 0 < sin(2x) < 1
 
 This shows that the output of sin(2x) must be between 0 and 1, which rules out w = -12 aka sin(2x) = -12
 Also, the range of sin(x) is
  . So even if we didn't have to worry about 0 < x < pi/4, it's still impossible to have sin(2x) = -12 (not unless we want to involve complex numbers, but we'll stay in the real number set). 
 We'll ignore w = -12 and go for w = 12/13 only.
 
 Therefore, sin(2x) = 12/13
 Isolating x gets us x = 0.5*arcsin(12/13)
 There are infinitely many solutions to sin(2x) = 12/13, but again we focus on the interval 0 < x < pi/4, which means we only have one solution.
 
 Note: arcsine is the same as inverse sine aka
 )  
 ----------------------------------------------------------
 
 Recall the ultimate goal is to find
  which we found was equivalent to   
 Plug in x = 0.5*arcsin(12/13) and simplify
 
   
 
   
 
   
 The question now is: how can we evaluate cot(arcsin(12/13))?
 
 Let theta = arcsin(12/13) which rearranges to sin(theta) = 12/13
 Since sine = opposite/hypotenuse, this gives us a right triangle with opposite leg 12 and hypotenuse 13.
 Use the pythagorean theorem to find the adjacent leg is 5 units.
 We have a 5-12-13 right triangle (this is one of the infinitely many pythagorean triples).
 
  Tangent is the ratio of opposite/adjacent
 the reciprocal is cotangent which is adjacent/opposite
 
 So cot(theta) = adjacent/opposite = 5/12
 which means,
 
   
 
 Therefore,
 
  when
  and   
 
 ----------------------------------------------------------
 ----------------------------------------------------------
 
 Answer: 5/6
 
 | 
  
 | 
 |