SOLUTION: If ln{ln[ln(lnx)]}=0, where the base of each natural log is e, then x=e^k. Find the positive real value of k.

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Question 1197491: If ln{ln[ln(lnx)]}=0, where the base of each natural log is e, then x=e^k. Find the positive real value of k.
Answer by ikleyn(52814) About Me  (Show Source):
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If ln{ln[ln(lnx)]}=0, where the base of each natural log is e, then x=e^k. Find the positive real value of k.
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If  ln{ln[ln(lnx)]} = 0,  then

       ln[ln(lnx)]  = 1,  then

          ln(ln(x)) = e, then

             ln(x)  = e%5E%28e%29,  then

                x   = e%5E%28e%5Ee%29.


The problem asks to find such real value "k" that

                x = e%5Ek = e%5E%28e%5Ee%29.


So, this value of "k" is  k = e%5Ee = 2.71828%5E2.71828 = 15.15421   (approximately).


ANSWER.   k = e%5Ee = 2.71828%5E2.71828 = 15.15421   (approximately).

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Solved.

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