SOLUTION: We wish to estimate what percent of adult residents in a certain county are parents. Out of 200 adult residents sampled, 68 had kids. Based on this, construct a 90% confidence inte

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Question 1197464: We wish to estimate what percent of adult residents in a certain county are parents. Out of 200 adult residents sampled, 68 had kids. Based on this, construct a 90% confidence interval for the proportion p of adult residents who are parents in this county.
Express your answer in tri-inequality form. Give your answers as decimals, to three places.
< p <
Express the same answer using the point estimate and margin of error. Give your answers as decimals, to three places.
p = ±
Answer by ewatrrr(24785) About Me  (Show Source):
You can put this solution on YOUR website!

Hi  
 n = 200,  p = 68/200 = .34  and q = .66 
90% confidence interval ⇒  z = 1.96  2-sided Invnorm(.95) = 1.645
ME = z%2Asqrt%28%28p%281-p%29%29%2Fn%29+=+1.645%2Asqrt%28%28.34%29%28.66%29%2F200%29%29= .055
.34 - .055 < p < .34 + .055
.285 < p < .395
 0r
p = .34 ± .055

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