SOLUTION: Suppose we want to estimate the proportion of teenagers (aged 13-18) who are lactose intolerant. If we want to estimate this proportion to within 3% at the 95% confidence level, ho

Algebra ->  Probability-and-statistics -> SOLUTION: Suppose we want to estimate the proportion of teenagers (aged 13-18) who are lactose intolerant. If we want to estimate this proportion to within 3% at the 95% confidence level, ho      Log On


   

Question 1197343: Suppose we want to estimate the proportion of teenagers (aged 13-18) who are lactose intolerant. If we want to estimate this proportion to within 3% at the 95% confidence level, how many randomly selected teenagers must we survey?
Answer by ewatrrr(24785) About Me  (Show Source):
You can put this solution on YOUR website!

Hi 
 95% confident ⇒  z = 1.96, 
p = .50(Generally .5 is used if p is not given)  ME = .03
How large of a sample size is required?
n = %28z%2FME%29%5E2+%28p%281-p%29%29%29
n = %281.96%2F.03%29%5E2+%28.5%28.5%29%29%29 = 1067.11  0r sample Size = 1068

 = CI	z = value
90%	z =1.645
92%	z = 1.751
95%	z = 1.96
98%	z = 2.326
99%	z = 2.576
Wish You the Best in your Studies.