SOLUTION: in a 3-digit number, the hundreds digit is one half of the tens digit. The ones digit is one more than the tens digit. If the sum of the digits is 11, find the number.

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Question 1197306: in a 3-digit number, the hundreds digit is one half of the tens digit. The ones digit is one more than the tens digit. If the sum of the digits is 11, find the number.

Found 2 solutions by MathLover1, Edwin McCravy:
Answer by MathLover1(20850) About Me  (Show Source):
You can put this solution on YOUR website!

let the tens digit be x
then
the hundreds digit is x%2F2
the ones digit is %28x%2B1%29
If the sum of the digits is 11, we have
x%2F2%2Bx%2B%28x%2B1%29=11...........solve for x
x%2F2%2B2x%2B1=11
x%2F2%2B2x=11-1
x%2F2%2B2x=10............both sides multiply by 2
x%2B4x=20
5x=20
x=4
the tens digit is 4
then
the hundreds digit is 4%2F2=2
the ones digit is %284%2B1%29=5
3-digit number is245

Answer by Edwin McCravy(20056) About Me  (Show Source):
You can put this solution on YOUR website!
Might know she'd do it for you instead of telling you how!
in a 3-digit number, the hundreds digit is one half of the tens digit.
h = 1%2F2t
The ones digit is one more than the tens digit.
u = t+1
If the sum of the digits is 11,
h+t+u = 11
find the number.
Substitute 1%2F2t for h, t+1 for u in

h+t+u = 11

1%2F2t + t + t+1 = 11

Solve that for t.
Then find h by substituting what you got for t in h = 1%2F2t.
Then find u by substituting what you got for t in u = t+1.

Then write h,t,u in a row in that order.

Edwin