SOLUTION: Suppose the area of the swimming pool is doubled, would its length and width also doubled? Justify your answer. The length is 35 and the width is 16

Algebra ->  Rectangles -> SOLUTION: Suppose the area of the swimming pool is doubled, would its length and width also doubled? Justify your answer. The length is 35 and the width is 16      Log On


   



Question 1197300: Suppose the area of the swimming pool is doubled, would its length and width also doubled? Justify your answer. The length is 35 and the width is 16
Found 2 solutions by math_helper, Theo:
Answer by math_helper(2461) About Me  (Show Source):
You can put this solution on YOUR website!

Clearly, no.
If A = L*W then if you double L and double W, you get:
(2L)*(2W) = 4(L*W) = 4*A (i.e. four times the original area).
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If the new swimming pool shape is similar to the old one, then L and W can be scaled by sqrt%282%29 to achieve a doubling of the area:
+%28sqrt%282%29%29+%2A+L+ * %28sqrt%282%29%29%2AW+ = +2%2AL%2AW+ = 2%2AA

Answer by Theo(13342) About Me  (Show Source):
You can put this solution on YOUR website!
area = length * width
multiply both sides of the equation by 2 to get:
2 * area = 2 * length * width
2 * length * width = 2 * width * length = (2 * length) * width or (2 * width) * length.
what this suggests is that either the length is multiplied by 2 or the width is multiplied by 2, but not both.
if the length is 35 and the width is 16, then the area is equal to 35 * 16 = 560.
2 time the area = 2 * 560 = 1120.
(2 * width) * length = 35 * 32 = 1120.
either the length is doubled or the width is doubled, but not both.
if both are affected equally, then both the length and the width are multiplied by sqrt(2).
35 * sqrt(2) * 16 * sqrt(2) = 35 * 16 * sqrt(2)^2 = 35 * 16 * 2.
either way, the length and the width are not doubled if the area is doubled.