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The relationship between the numbers of calculators x a company sells per day
and the price of each calculator p is given by the equation x = 500 - 100p
At what price should the calculators be sold so that the daily revenue is
to be $ 600? ( Show your steps)
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Under given conditions, the revenue is the product of the price per single calculator
by the number of calculators, sold per day,
Revenue = R(p) = p*(500-100p).
They want you find the price "p" from this equation
p*(500-100p) = 600.
Divide both sides by 100, then reduce to the standard form quadratic equation
p*(5 - p) = 6
-p^2 + 5p - 6 = 0
p^2 -5p + 6 = 0
Factor left side
(p-2)*(p-3) = 0.
There are two roots: p=2 and p=3.
They provide two solutions to your problem.
Solved.
