SOLUTION: A sum of money was to be shared among 3 persons A, B and C in the ratio 2:3:8 if C received $120 more than B find the sum of money shared

Algebra ->  Percentage-and-ratio-word-problems -> SOLUTION: A sum of money was to be shared among 3 persons A, B and C in the ratio 2:3:8 if C received $120 more than B find the sum of money shared       Log On


   

Question 1197168: A sum of money was to be shared among 3 persons A, B and C in the ratio 2:3:8 if C received $120 more than B find the sum of money shared

Found 2 solutions by josgarithmetic, ikleyn:
Answer by josgarithmetic(39630) About Me  (Show Source):
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PERSON       QUANTITY
A              2x
B              3x
C              8x=3x+120
SUM            ?


Note that the sum asked for is 13x.

8x-3x=120
5x=120
x=120%2F5
x=24

13x=13%2A24
13x=highlight%28312%29

Answer by ikleyn(52903) About Me  (Show Source):
You can put this solution on YOUR website!
.

Since we are given this triple proportion, we introduce 

    2x as an amount for A
    3x as an amount for B
    8x as an amount for C


After that, we have this equation

    8x - 3x = 120  dollars

which gives us

      5x    = 120

       x    = 120/5 = 24.


Thus,  A obtained  2*24 = 48 dollars;  B obtained 3*24 = 72 dollars and  C  obtained 8*24 = 192 dollars.   


The sum is  48 + 72 + 192 = 312 dollars.    ANSWER

Solved.