Question 1197081: Mr Willis had some orange and pears.60% of them were orange.70% of the pears and 40% of the orange were sold.240 fruit were not sold.how many fruit did Mr Willis have at first?
Found 4 solutions by ewatrrr, ikleyn, MathLover1, Theo:
Answer by ewatrrr(24785)   (Show Source):
You can put this solution on YOUR website!
Hi
Mr Willis had some orange and pears.
60% of them were oranges ⇒ .60T were Oranges, .40T were pears
70% of the pears and 40% of the orange were sold, 240 fruit were not sold
T = .70(.40T) + .40(.60T) + 240
T = .28T + .24T + 240
T - .52T = 240
.48T = 240
T = 240/.48 = 500 is how many fruit Mr Willis had at first
.28*500 + .24*500 + 240 = 500 checks
Wish You the Best in your Studies.
Answer by ikleyn(52884)  (Show Source):
You can put this solution on YOUR website! .
Mr Willis had some orange and pears.
60% of them were orange.
70% of the pears and 40% of the orange were sold.
240 fruit were not sold.how many fruit did Mr Willis have at first?
~~~~~~~~~~~~~~~
x = total fruits.
Number of oranges = 0.6x;
number of pears = 0.4x (the rest).
Number of oranges sold = 0.4*(0.6x) = 0.24x;
Number of pears sold = 0.7*(0.4x) = 0.28x.
Equation
x - 0.24x - 0.28x = 240 (the rest).
Simplify and find x
0.48x = 240
x = 240/48 = 500.
ANSWER. There were 500 fruits at first.
Solved.
Answer by MathLover1(20850)  (Show Source):
Answer by Theo(13342)  (Show Source):
You can put this solution on YOUR website! A = number of oranges
B = number of pears
A + B = total fruit = number of oranges plus number of pears
60% of the total were oranges, therefore A = .6 * (A + B)
40% of the total were pears, therefore B = .4 * (A + B)
70% of the pears and 40% of the oranges were sold, therefore:
number of fruits sold = .7 * B + .4 * A
rearrange to get:
number of fruits sold = .4 * A + .7 * B
therefore:
number of fruits not sold = .6 * A + .3 * B
240 fruit were not sold, therefore:
.6 * A + .4 * B = 240
since A = .6 * (A + B) and B = .4 * (A + B), you get:
.6 * .6 * (A + B) + .3 * .4 * (A + B) = 240
simplify to get:
.36 * (A + B) + .12 * (A + B) = 240
factor out the (A + B) to get:
(.36 + .12) * (A + B = 240
combine like terms to get:
.48 * (A + B) = 240
solve for (A + B) to get:
(A + B) = 240 / .48 = 500.
confirm as follows:
total fruit was 500.
60% of the fruit was oranges = .6 * 500 = 300
40% of the fruit was pears = .4 * 500 = 200
70% of the pears and 40% of the oranges were sold = .7 * 200 + .4 * 300 = 260
30% of the pears and 60% of the oranges were not sold = .3 * 200 + .6 * 300 = 240
260 sold and 240 not sold = 500 total.
solution is confirmed to be good.
solution is mr. willis had 500 fruits at first.
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